AP Physics

A centrifuge rotor rotating at 12000 rpm is shut off and is eventually brought to rest by a frictional torque of 1.50 m·N. If the mass of the rotor is 4.80 kg and it can be approximated as a solid cylinder of radius 0.0710 m, through how many revolutions will the rotor turn before coming to rest? How long will it take?

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  1. a. calculate the moment of inertia for the rotor (solid cylinder). Personnally, I recmmmend changing rpm to radians/sec

    Torque=momentI* angular acceleration
    solve for angular acceleration.

    Then,
    wfinal=winitial+ angAcc*time
    solve for time

    displacement=winitial*time+1/2 angacc;*time^2
    solve for displacement in radians, divide by 2PI to get revolutions.

    posted by bobpursley

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