A car of mass 800kg gose round a corner of radius 65m at a speed 10 m/s
what size force is needed to achive this?
F = m Ac = m v^2/R
= 800 (100)/65
= 1231 Newtons
Student.
1231
The car at the bend twice speed from the first ,the force it need m(2v)^2/r=800kg(20^2)m/s65m
A,b,c
To determine the size of the force needed to achieve this, we need to consider the centripetal force acting on the car.
The centripetal force is responsible for keeping an object moving in a circular path and can be calculated using the formula:
F = (m * v^2) / r
Where:
F is the centripetal force
m is the mass of the car (800 kg)
v is the velocity of the car (10 m/s)
r is the radius of the corner (65 m)
Plugging in the values into the formula, we can calculate the force:
F = (800 kg * (10 m/s)^2) / 65 m
Simplifying this equation gives us:
F = 800 kg * 100 m^2/s^2 / 65 m
Dividing 800 kg * 100 m^2/s^2 by 65 m, we get:
F ≈ 1230.77 N (rounded to two decimal places)
Therefore, the size of the force needed to achieve this is approximately 1230.77 Newtons.