sum of Rs.7700 is to be dividedamong three brothers Zain, Zaid and Zoaib in such a way that simple intereston each part at 5% per annum after 1,2 and 3 years, respectively remains equal. The share of Zain is more than that of Zoaib by?
To find the share of Zain that is more than Zoaib's share, we need to calculate the simple interest earned by each brother after 1, 2, and 3 years.
Let's calculate the share of each brother:
Let x be the share of Zain.
Then Zaid and Zoaib will also have a share of x, as the simple interest on each part remains equal.
After 1 year, Zain's share will be:
Principal = x
Rate of interest = 5%
Time = 1 year
Simple interest (SI) = Principal * Rate * Time
SI = x * 5/100 * 1
After 2 years, Zain's share will be:
Principal = x
Rate of interest = 5%
Time = 2 years
SI = x * 5/100 * 2
After 3 years, Zain's share will be:
Principal = x
Rate of interest = 5%
Time = 3 years
SI = x * 5/100 * 3
We know that the simple interest on each brother's share after 1, 2, and 3 years remains equal. Therefore,
x * 5/100 * 1 = x * 5/100 * 2 = x * 5/100 * 3
Simplifying this equation:
5x/100 = 10x/100 = 15x/100
We can see that 5x/100 = 15x/100.
Now, let's solve for x:
5x/100 = 15x/100
5x = 15x (Multiplying both sides by 100)
5x - 15x = 0
-10x = 0
x = 0
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