An inlet pipe can fill an empty pool in 3 hours. Another pipe can fill the same pool in 4 hours. How long will it take to fill the pool if both pipes are on?

how would this equation be set up?

time=1pool/(1pool/3 + 1pool/4)

Notice the rates add..1pool/4hrs + 1pool/3hrs.

time=12/7 hrs

8 hrs

A large pipe can fill a tank 10 minutes faster than it takes a smaller pipe to fill the same tank. Working together, both pipes can fill the tank in 12 minutes. How long would it take the large pipe working alone to fill the tank

To set up the equation for this problem, we can follow these steps:

1. Determine the individual rates at which each pipe can fill the pool.
- The first pipe can fill the pool in 3 hours, so its rate would be 1 pool per 3 hours, or 1/3 pool per hour.
- The second pipe can fill the pool in 4 hours, so its rate would be 1 pool per 4 hours, or 1/4 pool per hour.

2. Find the combined rate at which both pipes fill the pool when they are turned on together.
- To find the combined rate, add the rates of the individual pipes.
- So, the combined rate would be (1/3 + 1/4) pool per hour.

3. Set up the equation using the combined rate and the unknown time it takes to fill the pool when both pipes are turned on.
- Let's assume it takes x hours to fill the pool when both pipes are on.
- The equation would be: (1/3 + 1/4) * x = 1 (since we want to fill the entire pool, which is equivalent to 1 pool).

Now, you can solve this equation to find the value of x, which represents the time it takes to fill the pool when both pipes are turned on.