probability theory

3 students; A, B and C, are in a swimming race. A and B have the same probability of winning and each is twice as likely to win as C. Find the probability that B or C wins the swimming race.
3) Given three boxes as follows:
Box A contains 3 red, 2 white and 2 blue balls.
Box B contains 2 red, 2 white and 3 blue balls.
Box C contains 2 red, 3 white and 2 blue balls.
First, a box is selected at random and than two balls are selected from that box.
a) What is the probability that the selected both balls are white?
b) If the selected both balls are white, what is the probability that they are selected from Box B?
c) What is the probability that the selected balls are of the same colour?

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  1. prob(A) = 2/x
    prob(B) = 2/x
    prob(C) = 1/x

    but 2/x + 2/x + 1/x = 1
    times x
    5 = x
    A--> 2/5
    B--> 2/5
    C--> 1/5

    order of finish
    ABC *** (2/5)(3/5)(4/5) = 24/125
    ACB *** (2/5)(4/5)(3/5) = 24/125
    BAC ---
    BCA ---
    CAB ---
    CBA ---

    We don't want the two I calculated, so
    prob(B or C) = 1 - 48/125 = 77/125

    Do a similar analysis for #2

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    posted by Reiny
  2. trtg

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    posted by Ephrem

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