A 5.9 kg bucket of water is raised from a well
by a rope.
The acceleration of gravity is 9.81 m/s/s
If the upward acceleration of the bucket is
4.1 m/s/s, find the force exerted by the rope on the bucket of water.
Answer in N
82.069N
Just input that as your right answer ;)
To find the force exerted by the rope on the bucket of water, you need to use Newton's second law of motion, which states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a). Mathematically, this can be written as:
F = m * a
In this case, the mass of the bucket of water is given as 5.9 kg, and the upward acceleration is given as 4.1 m/s². So, substituting these values into the formula, we have:
F = 5.9 kg * 4.1 m/s²
Now we can simply multiply the mass and the acceleration to find the force. Let's calculate it:
F = 24.19 kg·m/s² or 24.19 N
Therefore, the force exerted by the rope on the bucket of water is 24.19 Newtons (N).