A 5.0 kg rock is dropped from the top of a building the speed of the rock after it has fallen for 4.2 seconds is _______meter per second
V = Vo + g*t.
Vo = 0.
g = 9.8 m/s^2.
V = ?
To find the speed of the rock after it has fallen for 4.2 seconds, you can use the equation for free fall:
v = gt
where:
v is the final velocity (speed) of the rock
g is the acceleration due to gravity (approximately 9.8 m/s^2)
t is the time
Given that the rock is in free fall, the acceleration due to gravity is acting on the rock. Therefore, we can use the equation above.
Plugging in the values:
v = (9.8 m/s^2) * (4.2 s)
v = 41.16 m/s (rounded to two decimal places)
Therefore, the speed of the rock after it has fallen for 4.2 seconds is approximately 41.16 m/s.