A rifle is aimed horizontally at a target 50m away. The bullet hits the target 2.0cm below the aim point.
A. What was the bullet's fight time?
B. What was the bullet's speed as it left the barrel?
see above.
To get the time use this:
T=(sqrt)of (2(.027m)/g
Now initial velocity formula:
V=d/t
V=52/.074=700.51-701m/s
700
wrong
To find the answers to these questions, we can use the equations of projectile motion. Since the rifle is aimed horizontally, the initial vertical velocity of the bullet is zero.
A. To determine the bullet's flight time, we need to find how long it takes for the bullet to reach the target. We can use the equation:
d = V₀t + 0.5at²
Where:
- d is the horizontal distance traveled (50m),
- V₀ is the initial horizontal velocity (which is equal to the bullet's speed since there is no acceleration in the horizontal direction),
- t is the flight time we are trying to find,
- a is the acceleration in the vertical direction (-9.8 m/s², assuming no air resistance).
Since the initial vertical velocity is zero, we can simplify the equation to:
50m = V₀ * t + 0.5 * (-9.8 m/s²) * t²
Simplifying further:
50m = -4.9t²
We can now solve for t by rearranging the equation:
t = sqrt(50m / -4.9m/s²)
Plugging the values into a calculator, we find:
t ≈ 3.19 seconds
Therefore, the bullet's flight time is approximately 3.19 seconds.
B. To find the bullet's speed as it left the barrel, we can use the equation:
d = V₀t
Rearranging the equation, we can solve for V₀ (the initial horizontal velocity):
V₀ = d / t
Plugging in the values:
V₀ = 50m / 3.19s
V₀ ≈ 15.67 m/s
Therefore, the bullet's speed as it left the barrel was approximately 15.67 m/s.