Question

If 1.65 M sulfuric acid is being used, how many mL of sulfuric acid will it take to fully react with 1.50 g of aluminum hydroxide?

Answer 1

2Al(OH)3 + 3H2SO4 ==> Al2(SO4)3 + 6H2O

mols Al(OH)3 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Al(OH)3 to mols H2SO4.
Then M H2SO4 = mols H2SO4/L H2SO4. You know M and mols, solve for L and convert to mL.