A high diver of mass 60.0 kg jumps off a board 10.0 m above the water. If her downward motion is stopped 2.10 s after she enters the water, what average force did the water exert on her?
avgforce*distance=Original energy=mgh
solve for avgforce.
686 N
To find the average force exerted by the water on the high diver, we can start by using the formula for average force:
Average force = Change in momentum / Time
First, let's determine the diver's momentum just before entering the water. We can calculate this using the equation:
Momentum = Mass × Velocity
The velocity of the diver just before entering the water can be found using the equation of motion:
Final velocity = Initial velocity + Acceleration × Time
In this case, the initial velocity is zero because the diver starts from rest. The acceleration can be found using the equation:
Acceleration = (Final velocity - Initial velocity) / Time
Since the diver comes to a stop in the water, their final velocity is also zero. Therefore, the acceleration and initial velocity are both zero, simplifying the equation to:
Acceleration = (0 - 0) / Time = 0
We can substitute this into the equation for final velocity:
Final velocity = 0 + 0 × Time = 0
Now we can calculate the momentum just before entering the water:
Momentum = Mass × Velocity = Mass × 0 = 0
Since there is no change in momentum, the change in momentum is also zero. So, the average force exerted by the water on the high diver is zero.
Therefore, the average force exerted by the water on the high diver is 0 N.