2. X - 7 > 10
X > ____
3. 3x ≤ 21
X ≤ ____
4.5a - 2 < 18
A<____
5. 2t+8 ≥ -4(t+1)
T ≥ ____
Could someone Please help me I have no idea how to do this
Certainly! I can help you with these inequality problems. Let's start solving them one by one.
2. X - 7 > 10
To solve this inequality, you need to isolate the variable X on one side of the inequality sign. Start by adding 7 to both sides of the inequality:
X - 7 + 7 > 10 + 7
This simplifies to:
X > 17
So, the solution for X is X > 17.
3. 3x ≤ 21
To solve this inequality, you need to isolate the variable X on one side of the inequality sign. Start by dividing both sides of the inequality by 3, since we are dividing by a positive number, the direction of the inequality sign won't change:
3x/3 ≤ 21/3
This simplifies to:
x ≤ 7
So, the solution for X is X ≤ 7.
4. 5a - 2 < 18
To solve this inequality, you need to isolate the variable A on one side of the inequality sign. Start by adding 2 to both sides of the inequality:
5a - 2 + 2 < 18 + 2
This simplifies to:
5a < 20
Next, divide both sides of the inequality by 5, again since it is a positive number, the direction of the inequality sign won't change:
(5a)/5 < 20/5
This simplifies to:
a < 4
So, the solution for A is A < 4.
5. 2t + 8 ≥ -4(t + 1)
To solve this inequality, you need to simplify the expression and then isolate the variable T on one side of the inequality sign. Let's start by distributing the -4 to (t + 1):
2t + 8 ≥ -4t - 4
Next, let's simplify the equation by combining like terms:
6t + 8 ≥ -4
Now, let's isolate the variable T by subtracting 8 from both sides of the inequality:
6t + 8 - 8 ≥ -4 - 8
This simplifies to:
6t ≥ -12
Lastly, divide both sides of the inequality by 6, again since it is a positive number, the direction of the inequality sign won't change:
(6t)/6 ≥ -12/6
This simplifies to:
t ≥ -2
So, the solution for T is T ≥ -2.
I hope this helps you understand how to solve these inequality problems!
X - 7 > 10
Add 7 to both sides
X > __17__
Study this site and the problem above.
http://www.mathsisfun.com/algebra/inequality-solving.html
I'll be glad to check your answers for the other problems.