is this the answer to B )
C2H5OH(liq)+ 3O2(g) --> 2CO2(g) +3H2O(liq)
In winemaking, the sugars in grapes undergo fermentation by yeast to yield CH3CH2OH and CO2. During cellular respiration, sugar and ethanol are "burned" to water vapor andCO2.
Write a combustion reaction for ethanol. INCLUDE PHYSICAL STATES
I need help with balancing the equation
i think it's
C2H6OH(l) + 3O2(g) ---> 2CO2(g) + 3H2O(g)
am I correct?..thanks!•chemistry - paul, Sunday, October 25, 2015 at 3:06pm
looks good to me, except the C2H6OH should be C2H5OH.
comment:
I did that, but it said...try again!
then it said HINT:
Start by writing a balanced chemical equation for the fermentation reaction of C6H12O6 and for the respiration reaction (combustion) of C6H12O6...what formula should be used to find the standard enthalpy of a reaction? Use the standard enthalpy of formation values from your textbook when calculating the standard enthalpy of reaction for both fermentation and respiration. thanks!
To balance the combustion reaction for ethanol (C2H5OH), follow these steps:
1. Write the unbalanced equation:
C2H5OH (l) + O2 (g) → CO2 (g) + H2O (g)
2. Begin by balancing the carbon atoms in the equation. Since there are two carbon atoms on the left side (in C2H5OH) and one carbon atom on the right side (in CO2), place a coefficient of 2 in front of CO2:
C2H5OH (l) + O2 (g) → 2CO2 (g) + H2O (g)
3. Next, balance the hydrogen atoms. There are six hydrogen atoms on the left side (in C2H5OH) and two hydrogen atoms on the right side (in H2O). Place a coefficient of 3 in front of H2O:
C2H5OH (l) + O2 (g) → 2CO2 (g) + 3H2O (g)
4. Finally, balance the oxygen atoms. There are two oxygen atoms on the left side (in C2H5OH) and four oxygen atoms on the right side (in 2CO2 and 3H2O). To balance the oxygen, you need to add a coefficient of 3/2 in front of O2:
C2H5OH (l) + (3/2) O2 (g) → 2CO2 (g) + 3H2O (g)
So, the balanced equation for the combustion of ethanol is:
C2H5OH (l) + (3/2) O2 (g) → 2CO2 (g) + 3H2O (g)
Regarding the hint about finding the standard enthalpy of the reaction, you can use the formula ΔH = ΣnΔHf(products) - ΣnΔHf(reactants), where ΔH is the change in enthalpy, Σn is the stoichiometric coefficient, and ΔHf is the standard enthalpy of formation. The standard enthalpy of formation values can be found in your textbook.