Write the slope-intercept (y = mx + b) form of the equation from the information given.
~~Slope equals 2 and the line goes through the point (-1, 3)
Can someone please show me how to do this?
Since you know the slope is 2, or m=2
so let's start with
y = 2x + b
we are told that (-1,3) lies on it, so
3 = 2(-1) + b
b = 5
equation: y = 2x + 5
Alright! Thank you sooo much!
To write the equation in slope-intercept form (y = mx + b) when given the slope and a point on the line, you can follow these steps:
Step 1: Start with the general form of a linear equation: y = mx + b, where m represents the slope and b represents the y-intercept that we need to find.
So far, we have y = 2x + b.
Step 2: Substitute the coordinates of the given point (-1, 3) into the equation for x and y.
By substituting the x-value (-1) and y-value (3), we have 3 = 2(-1) + b.
Step 3: Simplify the equation by performing the operations.
3 = -2 + b
Step 4: Isolate the variable b on one side of the equation.
To do this, we need to get rid of -2 on the right side of the equation. We can achieve this by adding 2 to both sides of the equation.
3 + 2 = -2 + b + 2
5 = b
Step 5: Rewrite the equation in slope-intercept form.
Now we have the value of b, which is 5. We can substitute it back into the equation y = 2x + b.
Therefore, the slope-intercept form of the equation with a slope of 2 and passing through the point (-1, 3) is y = 2x + 5.