Math
Find the solution.
1. sqrt2 sin x + 1 = 0
My ans: x = 5pi/4 + 2npi and 7pi/4 + 2npi
2. sec x  2 = 0
My ans: x = pi/3 + 2npi and 5pi/3 + 2npi
asked by
Anonymous
Respond to this Question
Similar Questions

PreCal(Please check)
1) Find all the solutions of the equation in the interval (0,2pi). sin 2x = sqrt3/2 I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them. 2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi Now I know that I 
PreCal(Please check)
1) Find all the solutions of the equation in the interval (0,2pi). sin 2x = sqrt3/2 I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them. 2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi Now I know that I 
PreCal (Please help)
Find all the soultions of the equation in the interval (0,2pi) sin 2x = sqrt3 /2 sin sqrt3 /2 is 4pi/3 and 5pi/3 in the unit circle 2x= 4pi/3 + 2npi 2x=5pi/3 + 2npi I do not know what to do at this point 
PreCal
Find all the soultions of the equation in the interval (0,2pi) sin 2x = sqrt3 /2 sin sqrt3 /2 is 4pi/3 and 5pi/3 in the unit circle 2x= 4pi/3 + 2npi 2x=5pi/3 + 2npi I do not know what to do at this point. 
trig
cos/sin use 2npi and tan uses npi, but how do you know when to add 2npi or npi to the solution of the equation? 
Math
1. Solve cos x(cos x  1) = 0. Ans: pi/2 + n pi, and 2 n pi 2. 2 cos x  1 = 0 Ans: x = pi/3 + 2 n pi, and x = 5pi/3 + 2 n pi 3. Solve 4 sin^2 x  3 = 0 Ans: x = pi/3 + n pi, and 2pi/3 + n pi 4. What is one solution to (sqrt2) 
Math Answer Check
1. Find the exact value of the expression. cos pi/16 * cos 3pi/16  sin pi/16 * sin 3pi/16 My ans: sqrt2/2 2. Find the exact value of the sin of the angle. 17pi/12 = 7pi/6 + pi/4 My ans: (sqrt2  sqrt6)/4 
Precalculus check answers help!
1. Which expression is equivalent to cos 2theta for all values of theta ? cos^2 theta – sin^2 theta ~ cos^2 theta – 1 1 – 2 sin^2 theta 2 sin theta cos theta 2. Use a half–angle identity to find the exact value of sin 
Math(Please help)
2) Use the sum and difference identites sin[x + pi/4] + sin[xpi/4] = 1 sinx cospi/4 + cosxsin pi/4 + sinx cos pi/4  cosx sin pi/4 = 1 2 sin x cos pi/4 =1 cos pi/4 = sqr2/2 2sin^x(sqrt2/2) = 1 sin x = sqrt2 x = 7pi/4 and 
Math(Please help)
1)tan Q = 3/4 Find cosQ 3^2 + 4^2 = x^2 9+16 = sqrt 25 = 5 cos = ad/hy = 4/5 Am I correct? 2) Use the sum and difference identites sin[x + pi/4] + sin[xpi/4] = 1 sinx cospi/4 + cosxsin pi/4 + sinx cos pi/4  cosx sin pi/4 =