A phone company offers two monthly charge plans. In Plan A, the customer pays a monthly fee of

$13
and then an additional
6
cents per minute of use. In Plan B, there is no monthly fee, but the customer pays
8
cents per minute of use.
For what amounts of monthly phone use will Plan A cost at least as much as Plan B?
Use
m
for the number of minutes of phone use in a month, and solve your inequality for
m
.

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A phone company charges 15 cents a minute to call a person long distance and a flat charge of 50 cents. If you want to spend no more than $5.00 on a phone call, write an inequality to represent this situation. *

To determine the point at which Plan A and Plan B would cost the same, we need to set up an equation based on the given information. Let's start by defining the cost (C) for each plan based on the minutes of phone use (m).

In Plan A, the customer pays a monthly fee of $13, plus an additional 6 cents per minute. So the cost for Plan A (CA) is:
CA = 13 + 0.06m

In Plan B, there is no monthly fee, but the customer pays 8 cents per minute. So the cost for Plan B (CB) is:
CB = 0.08m

To find the point where Plan A costs at least as much as Plan B, we want to solve the inequality CA ≥ CB.

13 + 0.06m ≥ 0.08m

Let's solve this inequality for m:

First, move all the terms involving m to one side of the inequality:

0.08m - 0.06m ≤ 13

Combine like terms:

0.02m ≤ 13

To isolate m, divide both sides of the inequality by 0.02:

m ≤ 13 / 0.02

Simplify:

m ≤ 650

Therefore, Plan A will cost at least as much as Plan B if the monthly phone use is 650 minutes or less.

For m minutes, we want A >= B. So

13+0.06m >= 0+0.08m

A phone company offers two monthly charge plans. In Plan A, the customer pays a monthly fee of

$5
and then an additional
4
cents per minute of use. In Plan B, there is no monthly fee, but the customer pays
6
cents per minute of use.
For what amounts of monthly phone use will Plan A cost at least as much as Plan B?
Use
m
for the number of minutes of phone use in a month, and solve your inequality for
m
.

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