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Determine the final end (final) value of n in a hydrogen atom transition, if electron starts in n = 1 and the atom absorbs a photon of light with an energy of 2.044 X 10^-18J?

thank you very much for your help

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  1. 1/wavelength = 1.9678 X 10^7 m^-1 (1/1-1/n^2)

    1/9.68 X 10^-8 = 1.09678 X 10^7 m^-1(1-1/n^2)

    Is this right , how to solve the rest ?

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  2. If you followed directions and put your SUBJECT in the School Subject box, a math/science tutor might have answered your questions by now.

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    Writeacher
  3. Determine the final end (final) value of n in a hydrogen atom transition, if electron starts in n = 1 and the atom absorbs a photon of light with an energy of 2.044 X 10^-18J?

    Here's the solution :)

    1/wavelength= Rh(1/n1^2-1/n2^2)
    speed of light = wavelength X frequency
    wavelength= speed/frequency

    Rh = 1.09678 X 10^7 (M-1)
    Energy = H X V
    2.044 X 10^-18 = 6.626 X 10^-34 X V
    --------------------
    V= 3.085 X 10^15
    --------------------
    1/wavelength =1.09678 X 10^7 (1-1/n2^2)
    1/speed/frequency = RH ( 1- 1/n2^2)
    frequency/Speed X RH = (1-1/n2^2)
    3.085 X 10^15 / 3 X 10^8 X 1.09687 X 10^7 =(1-1/n2^2)

    3.085 X 10^15 X 10^-8 X 10 ^-7 / 3 X 1.09678 = (1- 1/n2^2)
    0.938 = (1- 1/n2^2)
    1/n2^2 = 1-0.938 = 0.062
    n2^2 = 1/0.062 = 16
    n = 4

    you welcome

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