# Geometry

Two lines intersect so that angle 1 and angle 3 are vertical angles, angle 2 and angle 4 are vertical angles, and angle 1 and angle 2 form a linear pair. how do you slove for x and find the measure of all the angles when
angle 2= x sqaured -3x and angle 4= 6x=10

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1. <2 = x^2-3x
<4 = 6x+10

<2 = <4, so

x^2-3x = 6x+10
x^2-9x-10 = 0
(x-10)(x+1) = 0
x = 10 or -1

Now you can figure out the angles. Remember that

<1+<2 = <3+<4 = 180

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2. but how do i fin <1 and <3?

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3. Did you find <2?
If so, then read my last line above. <1 and <2 are supplementary.

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