Two lines intersect so that angle 1 and angle 3 are vertical angles, angle 2 and angle 4 are vertical angles, and angle 1 and angle 2 form a linear pair. how do you slove for x and find the measure of all the angles when
angle 2= x sqaured -3x and angle 4= 6x=10

please help it would mean a lot

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  1. <2 = x^2-3x
    <4 = 6x+10

    <2 = <4, so

    x^2-3x = 6x+10
    x^2-9x-10 = 0
    (x-10)(x+1) = 0
    x = 10 or -1

    Now you can figure out the angles. Remember that

    <1+<2 = <3+<4 = 180

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  2. but how do i fin <1 and <3?

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  3. Did you find <2?
    If so, then read my last line above. <1 and <2 are supplementary.

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