Shiloh has to earn at least $200 to meet her fundraising goal. She has only 100 cakes that she plans to sell at 5 dollars each. Which inequality shows the number of cakes, x, Shiloh can sell to meet her goal?
20 ¡Ü x ¡Ü 200
40 ¡Ü x ¡Ü 100
100 ¡Ü x ¡Ü 200
20 ¡Ü x ¡Ü 100
is it b
Yes, it is option B (40 ¡Ü x ¡Ü 100).
Shiloh has 100 cakes to sell at 5 dollars each. To meet her $200 goal, she needs to sell a certain number of cakes (x).
We can set up an inequality using her fundraising goal and the price per cake:
$5x >= $200
Now, we can solve for x:
x >= $200 / $5
x >= 40
Since she has only 100 cakes, the maximum number of cakes she can sell (x) is 100. Hence, the inequality becomes 40 ¡Ü x ¡Ü 100.
No, the correct answer is c) 100 ≤ x ≤ 200. Shiloh has only 100 cakes, so she can sell a minimum of 100 cakes. However, she needs to earn at least $200, which means she can sell a maximum of 200 cakes.
No, it is not option B. The correct inequality that shows the number of cakes, x, Shiloh can sell to meet her goal is:
100 ≤ x ≤ 200
To solve this inequality, we need to determine the minimum and maximum number of cakes Shiloh can sell to reach her goal.
We know that Shiloh has 100 cakes to sell, and each cake is sold for $5. Therefore, the minimum amount of money she can earn is 100 cakes multiplied by $5, which equals $500.
Since Shiloh needs to earn at least $200, the minimum number of cakes she needs to sell can be found by dividing $200 by $5, which equals 40 cakes.
Therefore, the minimum number of cakes Shiloh can sell is 40, and the maximum number of cakes she can sell is 100 (since that's all she has). So, the inequality becomes:
40 ≤ x ≤ 100
However, the question states that Shiloh needs to earn at least $200, which means the maximum number of cakes she can sell should allow her to reach or exceed $200. Since selling all 100 cakes would only yield $500, it satisfies the minimum requirement but exceeds the $200 target.
Therefore, the correct inequality is:
100 ≤ x ≤ 200