Two cars are initially 10.5 km apart on a straight road. If the cars are moving toward each other, car 1 with a speed of 9.5 m/s and car 2 with a speed of 10.40 m/s, how many seconds will it take before the cars meet?
10.5 km = 10,500 m.
V1*t + V2*t = 10,500.
9.5t + 10.4t = 10,500.
19.9t = 10,500.
t = 528 s.
To find the time it takes for the cars to meet, we need to determine the time it takes for car 1 and car 2 to cover the distance between them.
First, we need to convert the initial distance of 10.5 km into meters. Since 1 km equals 1000 m, 10.5 km is equal to 10.5 * 1000 = 10500 m.
Next, we can use the formula:
time = distance / speed
For car 1, the distance it needs to cover is the initial distance between the cars (10500 m). The speed of car 1 is given as 9.5 m/s. Therefore, the time it takes for car 1 to cover this distance is:
time1 = 10500 m / 9.5 m/s
Similarly, for car 2, the distance it needs to cover is also 10500 m, but the speed of car 2 is given as 10.40 m/s. Therefore, the time it takes for car 2 to cover this distance is:
time2 = 10500 m / 10.40 m/s
Finally, to find the total time it takes for the cars to meet, we can add the times for car 1 and car 2:
total time = time1 + time2
Now we can calculate the answer:
time1 = 10500 m / 9.5 m/s = 1105.26 s (rounded to two decimal places)
time2 = 10500 m / 10.40 m/s = 1009.62 s (rounded to two decimal places)
total time = 1105.26 s + 1009.62 s = 2114.88 s (rounded to two decimal places)
Therefore, it will take approximately 2114.88 seconds for the cars to meet.