the elevators in the landmark tower yokohama japan are among the fastest in the world. they accelerate upward at 3.125 m/s2 for 4.0 seconds to reach their final speed. if these elevators start at rest what is their final speed?
V = a*t = 3.125 * 4 = 12.5 m/s.
To find the final speed of the elevators, we can use the equation:
v = u + a*t
Where:
v = final speed
u = initial speed (which is zero in this case)
a = acceleration
t = time
Given:
Acceleration (a) = 3.125 m/s^2
Time (t) = 4.0 seconds
Plugging in these values into the equation, we have:
v = 0 + 3.125 * 4.0
v = 12.5 m/s
Therefore, the final speed of the elevators is 12.5 m/s.
To find the final speed of the elevators, we can use the kinematic equation:
vf = vi + at
Where:
vf = final speed
vi = initial speed (which is 0 since the elevators start at rest)
a = acceleration
t = time
Given:
a = 3.125 m/s² (acceleration)
t = 4.0 seconds (time)
Plugging in the values into the equation, we have:
vf = 0 + (3.125 m/s²)(4.0 s)
Simplifying the equation gives us:
vf = 12.5 m/s
Therefore, the final speed of the elevators is 12.5 m/s.