Find to the nearest degree, the size of each angle of regular heptagon
Four angle of a Pentagon are equal and the fifth is 60 degree .find the equal angle and show that two sides of the Pentagon are parallel
5*180 / 7
5*180/7
I need to known the nearest degree of heptagon
(7-2)*(180)
5*180/7
To find the size of each angle in a regular heptagon, we can use a formula that relates the number of sides in a regular polygon to its interior angles.
The formula is:
Interior angle = (n-2) * 180 / n
where "n" is the number of sides in the regular polygon.
For a regular heptagon, which has 7 sides, the formula becomes:
Interior angle = (7-2) * 180 / 7
Simplifying this equation will give us the size of each interior angle.
Interior angle = 5 * 180 / 7
Interior angle = 900 / 7
Interior angle ≈ 128.57 degrees
So, the size of each angle in a regular heptagon is approximately 128.57 degrees to the nearest degree.