calculus
a particle starts from rest and moves along a straight line with an acceleration equal to 2415√t where distance and time are measured in terms of feet and seconds respectively. with what acceleration will the particle return to the starting point?
help please thank you :)
asked by
jean

d=0=1/2 a t^2=12t^27.5t^3/2
t^2(127.5sqrtt)=0
sqrtt=12/7.5
t= that squared.
check my thinkingposted by bobpursley
Respond to this Question
Similar Questions

calculus
a particle starts from rest and moves along a straight line with an acceleration equal to 2415√t where distance and time are measured in terms of feet and seconds respectively. with what acceleration will the particle 
calculus
a particle starts from rest and moves along a straight line with an acceleration equal to 2415√t where distance and time are measured in terms of feet and seconds respectively. with what acceleration will the particle 
Maths
a particle starts from rest at o and moves in a straight line so that t seconds after, its velocity vm/s is given by v=2tt^2. given that particle comes instantanuously at rest at p. Find i) time taken to reach p? ii) the 
Calculus
1) A particle is moving along the xaxis so that its position at t ≥ 0 is given by s(t) = (t)In(2t). Find the acceleration of the particle when the velocity is first zero. 2) The driver of a car traveling at 50 ft/sec suddenly 
math
A particle moves along straight line such that its displacement S meters from a given point is S = t^3 – 5t^2 + 4 whee t is time in seconds. Find (a) The displacement of particle at t = 5 (b) The velocity of the particle when t 
Calculus
A particle moves in a straight line under a force such that its displacement s(t), in metres, at time t seconds, is given by s(t) = t3 − 5t2 + 3t +15 (i) Find the expression for the velocity of the particle. (ii) Find the 
calculus
a particle moves along a number line measured in cm so that its position at time t sec is given by s=72/(t+2) +k, k is a constant and t>=0 seconds. (a) Find the instantaneous velocity of the particle at t=4 seconds (b) Find the 
Calculus
A particle moves with velocity function v(t) = 2t^2 − 3t − 3, with v measured in feet per second and t measured in seconds. Find the acceleration of the particle at time t = 2 seconds. a)3/4 feet per second^2 b)1 feet per 
Calculus
A particle moves along the xaxis so that at any time t, measured in seconds, its position is given by s(t) = 5cos(t) − sin(3t), measured in feet. What is the acceleration of the particle at time t = π seconds? 
calculus
At t=0 , a particle starts at the origin with a velocity of 6 feet per second and moves along the xaxis in such a way that at time t its acceleration is 12t^2 feet per second per second. Through how many feet does the particle