calculus

a particle starts from rest and moves along a straight line with an acceleration equal to 24-15√t where distance and time are measured in terms of feet and seconds respectively. with what acceleration will the particle return to the starting point?

help please thank you :-)

asked by jean
  1. d=0=1/2 a t^2=12t^2-7.5t^3/2
    t^2(12-7.5sqrtt)=0
    sqrtt=12/7.5
    t= that squared.

    check my thinking

    posted by bobpursley

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