math

The product of both values of x for which 2003^x^2+2x-35 =1 is
A. -2
B. 2
C. -35
D. 35

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  1. I will assume you mean
    2003^(x^2 + 2x - 35) = 1
    then
    2003^(x^2 + 2x - 35) = 2003^0

    thus: x^2 + 2x - 35 = 0
    (x+7)(x-5) = 0
    x = -7 or x = 5

    and the product of those two x's is -35

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