The angle of depression of a boat from the mid-point of a vertical cliff is 35 degree.if the boat is 120m from the foot of the cliff,calculate the height of the cliff.help me confirm my answer.
Tan35=x/120
x=120tan35
=84.02m
Tan35=x/120
x=120tan35
=84.02m
height of cliff=2*x
=2*84.02
=168.02m
correct, but x is only halfway up the cliff . . .
Correct BT the work is nt too good
Students
wrong
Angle of depression 35 degree height of cliff
Tan=opp/adj tan 35=120/x
X= tan 35*120=84.02cm
To calculate the height of the cliff, we need to use trigonometric ratios. In this case, we will use the tangent ratio.
The tangent ratio states that the tangent of an angle is equal to the opposite side divided by the adjacent side. In this scenario, the angle of depression is 35 degrees, and the adjacent side is the distance from the boat to the foot of the cliff, which is given as 120m.
Using the tangent ratio, we can write:
tan(35) = height of the cliff / 120
To isolate the height of the cliff, we can rearrange the equation:
height of the cliff = 120 * tan(35)
Evaluating this expression, we find:
height of the cliff = 120 * 0.7002
height of the cliff ≈ 84.02m
So, your calculation is correct. The height of the cliff would be approximately 84.02 meters.