How many grams of NaCl are present in 1.5L of a 0.25M NaCl solution?
How many mols do you have? That's mols = M x L = ?
Then mols = grams/molar mass. You know molar mass and mols, solve for grams.
Mass of NaCl=?
Volume of solution=1.5litres
Molarity of solution=1.25M
To get the mass of NaCl,we need to find the mole.The relationship between molarity,volume and mole is given as: Molarity(M)=mole(n)/volume(v).
Making the unknown,mole, as subject of the formular;n=M X v
n=0.25 X 1.5 =0.375
But mass = molar mass X mole
molar mass of NaCl(23+35.5)=58.5
mole = 0.375
mass =58.5 X 0.375 =21.94g
To find the number of grams of NaCl in a solution, you can use the formula:
number of grams = (molarity in moles/Liter) x (volume in Liters) x (molar mass of NaCl)
First, let's find the number of moles of NaCl in the solution:
moles of NaCl = (molarity) x (volume in liters)
Given that the molarity is 0.25M and the volume is 1.5L:
moles of NaCl = 0.25M x 1.5L
Next, we need to find the molar mass of NaCl, which is the sum of the atomic masses of sodium (Na) and chlorine (Cl):
molar mass of NaCl = (atomic mass of Na) + (atomic mass of Cl)
The atomic mass of Na is 22.99 g/mol and the atomic mass of Cl is 35.45 g/mol, so:
molar mass of NaCl = 22.99 g/mol + 35.45 g/mol
Now, we can calculate the number of grams of NaCl:
number of grams of NaCl = (moles of NaCl) x (molar mass of NaCl)
Plug in the values we found earlier:
number of grams of NaCl = (0.25M x 1.5L) x (22.99 g/mol + 35.45 g/mol)
Simplifying the expression:
number of grams of NaCl ≈ 13.61 g