A can is 12cm high and diameter 8cm. Using the formula v =TT how much liquid is in the can
I have no clue what v =TT is supposed to say, but my formula for volume of a cylinder is
V = πr^2 h
so for your data,
V = π(4^2)(12)
= 192π
so your can holds a volume of 192π cm^3
which is 192π ml or appr 603.2 ml
To calculate the volume of liquid in the can, we can use the formula for the volume of a cylinder, which is given as:
V = πr^2h
Where:
V: Volume
π: Pi (approximately 3.14)
r: Radius of the base (half of the diameter)
h: Height of the cylinder
Given that the can has a height of 12cm and a diameter of 8cm, we can calculate the radius by dividing the diameter by 2:
r = 8cm / 2 = 4cm
Now, we can substitute the values into the formula:
V = π(4cm)^2(12cm)
V = 3.14 × 16cm^2 × 12cm
V = 602.88cm^3
Therefore, the volume of liquid in the can is approximately 602.88 cubic centimeters.
To find the volume of the liquid in the can, we can use the formula for the volume of a cylinder. The formula is V = πr^2h, where V is the volume, π is approximately 3.14159, r is the radius of the cylinder (half of the diameter), and h is the height of the cylinder.
In this case, the height of the can is given as 12 cm and the diameter is given as 8 cm. We need to find the radius before we can calculate the volume.
The radius (r) is half the diameter, so r = 8 cm / 2 = 4 cm.
Now we can substitute the values into the formula:
V = πr^2h
≈ 3.14159 × 4^2 × 12
≈ 3.14159 × 16 × 12
≈ 603.18576 cm^3
Therefore, the volume of the liquid in the can is approximately 603.19 cm^3.