que.1-10 g of a mixture of Bao and Cao require 100ml of 2.5M Hcl to react with it.Find out the amount of Bao in %.
Thanks for explaining it is easy to understand.
To find out the amount of BaO in the mixture, we need to determine how much BaO reacted with the 100 mL of 2.5 M HCl.
First, let's start by understanding the chemical equation representing the reaction between BaO and HCl:
BaO + HCl → BaCl2 + H2O
From the balanced equation, we can see that 1 mole of BaO reacts with 2 moles of HCl to produce 1 mole of BaCl2.
Given that we have used 100 mL of 2.5 M HCl, we can calculate the number of moles of HCl used:
Molarity (M) = moles/volume (L)
2.5 M = moles/0.1 L
moles = 2.5 M * 0.1 L = 0.25 moles
Since 1 mole of BaO reacts with 2 moles of HCl, we know that the number of moles of BaO present in the mixture is equal to half the number of moles of HCl used:
moles of BaO = 0.25 moles / 2 = 0.125 moles
Now, to calculate the amount of BaO in grams, we need to know its molar mass. The molar mass of BaO can be calculated as:
Molar mass of BaO = atomic mass of Ba + atomic mass of O
Molar mass of BaO = 137.33 g/mol + 16.00 g/mol = 153.33 g/mol (approx.)
Finally, we can determine the mass of BaO in the mixture using the equation:
Mass of BaO = moles of BaO * molar mass of BaO
Mass of BaO = 0.125 moles * 153.33 g/mol = 19.17 g (approx.)
Therefore, the amount of BaO in the mixture is approximately 19.17 grams.
To calculate the percentage of BaO in the mixture, we divide the mass of BaO by the initial mass of the mixture and multiply by 100:
Percentage of BaO = (mass of BaO / initial mass of mixture) * 100
Percentage of BaO = (19.17 g / 10 g) * 100 = 191.7 %
Therefore, the amount of BaO in the mixture is approximately 191.7%.
This is a mixture problem. It requires two equation to be solved simultaneously.
Let X = mass BaO
ad Y = mass CaO
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equation 1 is X + Y = 10g
The second equation comes from the reaction with HCl.
2HCl + BaO ==> BaCl2 + H2O
2HCl + CaO ==> CaCl2 + H2O
You want to equation mols BaO and mols CaO to total mols of HCl reacted. mols HCl reacted = M x L = 2.5 x 0.1 = 0.25.
mols HCl reacting with BaO = X*2/molar mass BaO
mols HCl reacting with CaO = X*2/molar mass CaO
Total then is
(2X/molar mass BaO) + (2X/molar mass CaO) = 0.25 and that is the second equation.
Solve equation 1 and equation 2 simultaneously for X and Y.
Then %BaO = (mass BaO/mass sample)
%BaO = (X/10)*100 = ?