The distance between the midpoints of two metal balls,P and Q,respectively of masses 55 kg and 70 kg,is 80 cm (a)calculate the gravitational force that P exerts on Q thanks in advance
I'm looking for physical sciences solutions.
d = .8 meter
so
F = G *55*70 /(.64)
where G = 6.67*10^-11 m^3 /(kg s^2)
To calculate the gravitational force that P exerts on Q, we can use the formula:
F = (G * m₁ * m₂) / r²
Where:
- F is the gravitational force
- G is the gravitational constant (6.67430 x 10^-11 N(m/kg)²)
- m₁ is the mass of object P (55 kg)
- m₂ is the mass of object Q (70 kg)
- r is the distance between the midpoints of the two objects (80 cm = 0.8 m)
Substituting the given values into the formula:
F = (6.67430 x 10^-11 N(m/kg)² * 55 kg * 70 kg) / (0.8 m)²
Calculating the gravitational force:
F = (6.67430 x 10^-11 N(m/kg)² * 55 kg * 70 kg) / (0.64 m²)
F = 4.9195 x 10^-8 N
Therefore, the gravitational force that P exerts on Q is approximately 4.9195 x 10^-8 Newtons.
To calculate the gravitational force between two objects, you can use Newton's law of universal gravitation formula:
F = G * (m1 * m2) / r^2
Where:
F is the gravitational force
G is the gravitational constant (6.674 × 10^-11 Nm^2/kg^2)
m1 and m2 are the masses of the two objects
r is the distance between the centers of the two objects
In this case, we are given:
m1 = 55 kg (mass of ball P)
m2 = 70 kg (mass of ball Q)
r = 80 cm = 0.8 m (distance between the midpoints)
Plugging the values into the formula, we have:
F = (6.674 × 10^-11 Nm^2/kg^2) * (55 kg * 70 kg) / (0.8 m)^2
Now, let's calculate:
F = (6.674 × 10^-11) * (3850) / (0.8)^2
F = (6.674 × 10^-11) * (3850) / 0.64
F ≈ 1.036 N
Therefore, the gravitational force that ball P exerts on ball Q is approximately 1.036 Newtons.