Fuel wood logs sawed 53 times and 72 pieces made. If the cutter saw only one at a time how many there were before cutting?
71
ans is 18 but how it calutated
so how many more pieces than cuts?
72 - 53 = 19
bu you have one more piece than cuts
so 18
To solve this problem, we need to use some simple arithmetic. Let's break it down step by step:
Step 1: Start with the information provided in the question. The fuel wood logs were sawed 53 times, and 72 pieces were made.
Step 2: We know that each time the cutter saws a log, it cuts it into two pieces. So, if we saw a log once, we get two pieces.
Step 3: To find out how many logs were there before cutting, we need to work backward. Since each sawing operation doubles the number of pieces, we can say that each sawing operation reduces the number of logs by half.
Step 4: Therefore, if 72 pieces were made after 53 sawing operations, we need to determine how many logs we started with before any sawing.
Step 5: To find the original number of logs, we divide the number of pieces (72) by the number of pieces obtained from each log sawing operation (2).
72 pieces / 2 pieces = 36 logs.
So, there were initially 36 logs before the cutting operation started.