1/b (2b-10)=17
Multiply both sides by b:
2b-10 = 17b
1/b(2b-10) = 17
Multiply both sides by b:
2b-10 = 17b
15b = -10
b = -2/3
To solve the equation 1/b(2b-10) = 17, we can follow these steps:
Step 1: Simplify the equation by multiplying both sides by b to eliminate the denominator:
1/b(2b - 10) * b = 17 * b
(2b - 10) = 17b
Step 2: Distribute the b on the left side of the equation:
2b * 1 - 10 * 1 = 17b
2b - 10 = 17b
Step 3: Move all the terms with b to one side of the equation by subtracting 17b from both sides:
2b - 17b - 10 = 17b - 17b
-15b - 10 = 0
Step 4: Combine like terms on the left side of the equation:
-15b - 10 = 0
-15b = 10
Step 5: Solve for b by dividing both sides of the equation by -15:
-15b / -15 = 10 / -15
b = -10/15
Therefore, the solution to the equation is b = -10/15, which can also be simplified to b = -2/3.