Calculate the electrical attraction that a proton in a nucleus exerts on an orbiting electron if the two particles are 1.13×10^-10 m apart.

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asked by Erin
  1. Use Coulomb's Law:

    !@#$%^&*Q1*Q2 / r^2

    k = 9.00x10^9 N.m^2/C^2 (Coulomb's constant)
    Q1 = Q2 = 1.60x10^-19C (Elementary charge)
    r = given in the question (distance)

    Note: The charge of a proton is equal to the charge of an electron except for the algebraic sign.

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    posted by GK
  2. I tried that and got 1.8x10^8 but it wasn't the right answer

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    posted by erin
  3. You didn't do it right. Just doing the orders of magnitude only..

    F=E9*E-19*E-19/E-20 ( I squared the distance)
    F=E(9-38+20) appx 10^-9 Newtons.

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  4. what does E mean? Could you explain it another way because I'm confused.

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    posted by Erin
  5. >.< ?

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    posted by coco

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