AP Chemistry

In a chemical atomic weight determination, the tin content of 3.7692 g of SnCl4 was found to be 1.7170 g. If the atomic weight of Chlorine is taken as 35.253, what is the determined value for the atomic weight of tin from this experiment?

I already know the answer, 118.64. It was given. What I'm stuck on is the process. Can somebody explain how to set this up? Thanks.

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asked by John
  1. 0.0145533713 is the number of moles of Sn present, found from the fact that the number of moles of Sn is 1/4 the number of moles of Cl (massCl/molmassCl)

    MolmassSn=massSn/numbermolesSn
    117.98 according to the numbers. Check my thinking.

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