The data in the table are linear. Use the table to find the slope.
X| 2| 4| 6| 8
Y| 1|-2|-5|-8
A. 3/2
B. -3/2
C. -2/3
D. 2/3
Please help me work this out I don't know how to do this kind of stuff. Thank you in advance.
C
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Answers may change so make sure to double check
the furry is right not their real name but i dont want to type it ok, ok
Thank you Reiny. They put me in this math class and I can't do this stuff and the year is almost over.
i need the answers please!!!!(i beg of you some one please!!!!!!!
Yes, I can definitely explain it step by step.
We are given the following table:
```
X | 2 | 4 | 6 | 8
---|-----|-----|-----|----
Y | 1 | -2 | -5 | -8
```
To find the slope, we need to use the formula:
slope = (change in y)/(change in x)
We can choose any two points from the table to calculate the slope. Let's choose the first two points (2,1) and (4,-2).
To calculate the change in y, we subtract the y-coordinates of the two points:
change in y = y2 - y1 = -2 - 1 = -3
To calculate the change in x, we subtract the x-coordinates of the two points:
change in x = x2 - x1 = 4 - 2 = 2
Now we can substitute these values into the formula for slope:
slope = (change in y)/(change in x) = -3/2
Therefore, the slope of the line is -3/2.
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UwU *Nuzzles* Is correct.
And Jake from state farm I hope you know you being on here like everyone else on here means that what you said to @reiny goes for u too. 😉
right 2022 3/11/2022
UwU is right, use their answers
Sure, I'd be happy to explain how to solve the problem step by step.
To find the slope of a line that is parallel to another line, we need to use the fact that parallel lines have the same slope. So, we can start by finding the slope of the line that passes through the points (3,4) and (2,6):
slope = (change in y) / (change in x)
slope = (6 - 4) / (2 - 3)
slope = -2
The slope of this line is -2. This means that any line that is parallel to this line will also have slope -2.
So, the answer to the problem is that the slope of a line that is parallel to the line containing the points (3,4) and (2,6) is -2.