The data in the table are linear. Use the table to find the slope.

X| 2| 4| 6| 8
Y| 1|-2|-5|-8

A. 3/2
B. -3/2
C. -2/3
D. 2/3
Please help me work this out I don't know how to do this kind of stuff. Thank you in advance.

C

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Answers may change so make sure to double check

the furry is right not their real name but i dont want to type it ok, ok

Thank you Reiny. They put me in this math class and I can't do this stuff and the year is almost over.

i need the answers please!!!!(i beg of you some one please!!!!!!!

Yes, I can definitely explain it step by step.

We are given the following table:

```
X | 2 | 4 | 6 | 8
---|-----|-----|-----|----
Y | 1 | -2 | -5 | -8
```

To find the slope, we need to use the formula:

slope = (change in y)/(change in x)

We can choose any two points from the table to calculate the slope. Let's choose the first two points (2,1) and (4,-2).

To calculate the change in y, we subtract the y-coordinates of the two points:

change in y = y2 - y1 = -2 - 1 = -3

To calculate the change in x, we subtract the x-coordinates of the two points:

change in x = x2 - x1 = 4 - 2 = 2

Now we can substitute these values into the formula for slope:

slope = (change in y)/(change in x) = -3/2

Therefore, the slope of the line is -3/2.

C

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UwU *Nuzzles* Is correct.

And Jake from state farm I hope you know you being on here like everyone else on here means that what you said to @reiny goes for u too. πŸ˜‰

right 2022 3/11/2022

UwU is right, use their answers

Sure, I'd be happy to explain how to solve the problem step by step.

To find the slope of a line that is parallel to another line, we need to use the fact that parallel lines have the same slope. So, we can start by finding the slope of the line that passes through the points (3,4) and (2,6):

slope = (change in y) / (change in x)

slope = (6 - 4) / (2 - 3)

slope = -2

The slope of this line is -2. This means that any line that is parallel to this line will also have slope -2.

So, the answer to the problem is that the slope of a line that is parallel to the line containing the points (3,4) and (2,6) is -2.

Sure, I can explain how to find the slope of a line that is perpendicular to the line containing the points (-2,-1) and (2,-3) step by step.

To find the slope of a line that is perpendicular to another line, we can use the fact that perpendicular lines have slopes that are negative reciprocals of each other.

Step 1: Find the slope of the line containing the points (-2,-1) and (2,-3)

slope = (change in y)/(change in x)
= (-3 -(-1)) / (2 -(-2))
= -2 / 4
= -1/2

So, the slope of the line containing the points (-2,-1) and (2,-3) is -1/2.

Step 2: Find the negative reciprocal of -1/2

The negative reciprocal of a number is found by flipping the fraction and changing its sign.

The negative reciprocal of -1/2 is 2/1, or simply 2.

Therefore, the slope of the line that is perpendicular to the line containing the points (-2,-1) and (2,-3) is 2.

UwU *Nuzzles*

Is right for the Connexus question show above

RAHHHHHHHHHHHH

i didn't get this it makes no sense, 2 times -3/2 doesn't equal 1

I apologize for the confusion. I believe there was a mistake in the calculation.

To find the slope using the table, we can use any two points. Let's take the points (2,1) and (4,-2):

slope = (change in y)/(change in x)
= (-2 -1)/(4 - 2)
= -3/2

Therefore, the slope of the line is -3/2.

wait i dont understand can you explain step by step

bot please help and explain step by step!!!

find the slope of a line that is parallel to the line containing the points (3,4) and (2,6).

please explain step by step, find the slope of a line that is perpendicular to the line containing the points (-2,-1) and 2,-3)

@ reiny, if ur so smart why are u on this website huh

by the way... TYSM UwU *Nuzzles*

and also, no offence @reiny

tysm UwU *nuzzles*

*Nuzzles back* :3

use the first two ordered pairs, since we are told the function is linear

(2,1) and (4,-2)

slope = (-2-1)/(4-2) = -3/2

To hear , " I don't know how to do this kind of stuff" is not a good thing.
Finding slope between any two points is fundamental and pretty basic.