What mass of KCl in grams is formed when 2.00lbs of KClO3 is decomposed?
1. Write and balanced the equation.
2. Convert 2 lb KClO3 to grams.
3. Convert g KClO3 to mols. mols = grams/molar mass
4. Using the coefficients in the balanced equation, convert mols KClO3 to mols KCL.
5. Convert mols KCl to grams via g = mols KCl x molar mass KCl = ?
To find the mass of KCl formed when 2.00 lbs of KClO3 is decomposed, we need to use stoichiometry.
1. Convert 2.00 lbs to grams:
- 1 lb = 453.592 grams
- 2.00 lbs = 2.00 x 453.592 grams = 907.184 grams
2. Write the balanced equation for the decomposition of KClO3:
2 KClO3 --> 2 KCl + 3 O2
3. Determine the molar mass of KClO3 and KCl:
- KClO3: K (39.10 g/mol) + Cl (35.45 g/mol) + 3 O (16.00 g/mol) = 122.55 g/mol
- KCl: K (39.10 g/mol) + Cl (35.45 g/mol) = 74.55 g/mol
4. Use the stoichiometry of the balanced equation to find the mass of KCl formed:
- From the balanced equation, we know that 2 moles of KClO3 will produce 2 moles of KCl.
- 2 moles of KClO3 = 2 x 122.55 g = 245.10 g KClO3
- According to the stoichiometry, 2 moles of KClO3 will produce 2 moles of KCl.
- Therefore, 245.10 g KClO3 will produce 2 x 74.55 g = 149.10 g KCl.
Thus, when 2.00 lbs of KClO3 is decomposed, 149.10 grams of KCl is formed.