if you dissolve 9 mg of glucose in 5 ml of water .what is the concentration of glucose in %w\v the resulting solution?
9 mg = 0.009 g
(0.009g/5 mL)*100 = ?%w/v
To determine the concentration of glucose in %w/v (weight/volume) in the resulting solution, you need to follow these steps:
Step 1: Calculate the mass of glucose in grams
To convert mg to grams, divide the given mass by 1000:
9 mg = 9/1000 g = 0.009 g
Step 2: Calculate the volume of the resulting solution in milliliters
The volume of the resulting solution is given as 5 ml.
Step 3: Calculate the concentration %w/v
The %w/v concentration is calculated by dividing the mass of solute (glucose) by the volume of the solution, and then multiplying by 100.
%w/v = (mass of solute/volume of solution) × 100
In this case:
%w/v = (0.009 g / 5 ml) × 100
Now, divide the mass of the solute (glucose) by the volume of the solution:
%w/v = 0.009 g / 5 ml
Divide the values:
%w/v = 0.0018 g/ml
Finally, multiply the result by 100 to convert it to a percentage:
%w/v = 0.0018 g/ml × 100 = 0.18 %w/v
Therefore, the concentration of glucose in the resulting solution is 0.18 %w/v.