# Steve - Stat

A Bacteria has a doubling period of 8 days. If there are 2250 bacteria present now, how many will there be in 33 days?
find the growth rate (Round this to 4 decimal places).
Growth Rate___________.
There will be _________ Bacteria.

The growth rate you posted is showing up as incorrect? the first count is showing as correct.

Since it grows by a factor of 2 every 8 days, the population is

2250 * 2^(t/8)
In 33 days there will be 39258

The growth factor for each day is 2^(1/8) = 1.0905, for a 9.05% per day growth rate

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1. 9.0508%

2250 * 1.0905077^33 = 39258

showing the proper growth rate. Maybe they don't want a percent, but a factor?

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posted by Steve

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