A Bacteria has a doubling period of 8 days. If there are 2250 bacteria present now, how many will there be in 33 days?

find the growth rate (Round this to 4 decimal places).
Growth Rate___________.
There will be _________ Bacteria.

The growth rate you posted is showing up as incorrect? the first count is showing as correct.

Since it grows by a factor of 2 every 8 days, the population is

2250 * 2^(t/8)
In 33 days there will be 39258

The growth factor for each day is 2^(1/8) = 1.0905, for a 9.05% per day growth rate

9.0508%

2250 * 1.0905077^33 = 39258

showing the proper growth rate. Maybe they don't want a percent, but a factor?

To find the growth rate, we can use the formula:

Growth Rate = 2^(1/days)

In this case, the doubling period is 8 days. So we can calculate the growth rate as:

Growth Rate = 2^(1/8) ≈ 1.0905 (rounded to 4 decimal places)

Therefore, the growth rate is approximately 1.0905.

To calculate the number of bacteria after 33 days, we can use the formula:

Final Number of Bacteria = Initial Number of Bacteria * Growth Rate^(days/doubling period)

Given that the initial number of bacteria is 2250, the doubling period is 8 days, and the number of days is 33, we can substitute these values into the formula:

Final Number of Bacteria = 2250 * 1.0905^(33/8) ≈ 39258

Therefore, there will be approximately 39258 bacteria in 33 days.

To find the growth rate, we can use the formula:

Growth Rate = (Final Bacteria Count / Initial Bacteria Count)^(1/Time)

In this case, the final bacteria count is the unknown we want to find, the initial bacteria count is 2250, and the time is 33 days.

So, to find the growth rate, let's plug in the values into the formula:

Growth Rate = (Final Bacteria Count / Initial Bacteria Count)^(1/Time)
Growth Rate = (Final Bacteria Count / 2250)^(1/33)

Now, let's solve for the growth rate:

Growth Rate = (Final Bacteria Count / 2250)^(1/33)
Growth Rate^33 = Final Bacteria Count / 2250
Final Bacteria Count = 2250 * Growth Rate^33

Next, let's calculate the growth rate using the doubling period of 8 days:

Growth factor for each day = 2^(1/8) = 1.0905

Now, we can substitute this value into the equation:

Final Bacteria Count = 2250 * 1.0905^33

Calculating this value, we find:

Final Bacteria Count ≈ 39,258

Therefore, the growth rate rounded to 4 decimal places is approximately 1.0905, and there will be approximately 39,258 bacteria in 33 days.