# physics

An object uniformly accelerates at a rate of 1.20m/s^2 east. While accelerating at this rate, the object is displaced 470.4m east in a time of 28 s. What velocity did this object reach in this time ?

I used Vf=Vi+at
which will be Vf=(1.20)(28)
but i feel this isn't the way to solve it
please help
Thanks!

asked by Dania
1. Vf^2=Vi^2 +2ad

so the question is, what is Vi?

consider vf=vi+at
Now you have two equations, two unknowns, Vf, and Vi.

I would solve for Vi in the second equation, then put that in the first equation and solve for Vf

posted by bobpursley

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