physics

An object uniformly accelerates at a rate of 1.20m/s^2 east. While accelerating at this rate, the object is displaced 470.4m east in a time of 28 s. What velocity did this object reach in this time ?


I used Vf=Vi+at
which will be Vf=(1.20)(28)
but i feel this isn't the way to solve it
please help
Thanks!

asked by Dania
  1. Vf^2=Vi^2 +2ad

    so the question is, what is Vi?

    consider vf=vi+at
    Now you have two equations, two unknowns, Vf, and Vi.

    I would solve for Vi in the second equation, then put that in the first equation and solve for Vf

    posted by bobpursley

Respond to this Question

First Name

Your Answer

Similar Questions

  1. physics

    Question: Object A is moving at a maximum speed of 6m/s towards Object B. At 50 m away Object B accelerates from the approaching Object A at 0.3m/s^2. Does Object A catch up to Object B and if yes when? I don't know how to answer
  2. physics

    an object accelerates uniformly along a straight line from a velocity of 10ms-1 until 25ms-1 in 5s. a)the velocity of the object during the first 10s of motion b)the time taken to reach a final velocity 50ms-1
  3. Physics

    object A of mass 3g with a velocity of 12cm/s to the east, collides with stationary object B. After collision, object A rebounds with a velocity of 10cm/s to the west and object B has a velocity of 1.5cm/s to the east. Calculate
  4. Physics

    An object at rest accelerates through a distance of 1.5 m at which point the instantaneous velocity of the object is 3.5m/s. Determine: a. The average acceleration of the object b. The time it took the object to travel 1.5m c. The
  5. Physics

    An object at rest accelerates through a distance of 1.5 m at which point the instantaneous velocity of the object is 3.5m/s. Determine: a. The average acceleration of the object b. The time it took the object to travel 1.5m c. The
  6. calculus help check and help

    if an object with mass m is dropped from rest, one model for its speed v after t seconds, taking air resistance into account is v= mg/c(1-e^(-ct/m)) where g is the acceleration due to gravity and c is a positive constant
  7. science

    Object A and B both start at rest. They both accelerate at the same rate. However , object A accelerates for twice the time as object B. What is the distance traveled by object A compared to that of object B? a) the same distance
  8. Science

    4: Which of the following is true of an object in a circular motion at a constant speed? A: The net force on the object is zero B: The object is not accelerating as the speed of the object remains the same C:the object is
  9. Physics

    (a) At a certain instant, a particle-like object is acted on by a force F=(2.9N)i-(1.7N)j+(5.7N)k while the object's velocity is v= -(3.2m/s)i+(4.5m/s)k. What is the instantaneous rate at which the force does work on the object?
  10. Physics

    At a certain instant, a particle-like object is acted on by a force F = (4.0 N) - (2.0 N) + (9.0 N) while the object's velocity is v = - (2.0 m/s) + (4.0 m/s) . What is the instantaneous rate at which the force does work on the

More Similar Questions