I was given this info
r=1.5 m
d=3 m
F= 50 N
angle= 110 degrees
1. What torque is applied?
T=Fsin
T= (1.5)(50)sin(110)
T=70 J
2. At what angle would enough force be applied to achieve maximum toque?
T=Fsin
T= (1.5)(50)sin(90)
T=75 (joules)
3. If someone continues to push with a force of 50 N, what maximum torque could be applied?
T=Fsin
T= (1.5)(50)sin(10)
T=13.0 J
Are these solutions to the questions correct, if not; what do i need to change to get the correct solution?
The solution to the first question is correct. The torque applied can be calculated using the equation T = F*sin(angle), where F is the force and angle is the angle between the applied force and the lever arm.
However, the solutions to the second and third questions are incorrect.
For the second question, you are asked to find the angle at which enough force is applied to achieve maximum torque. In this case, the force is given as 50 N. The formula for torque remains the same: T = F*sin(angle).
To find the angle that maximizes the torque, you need to maximize the value of sin(angle). The maximum value of sin(angle) is 1, which occurs when angle = 90 degrees or π/2 radians. Therefore, to achieve maximum torque, the force must be applied perpendicular to the lever arm.
For the third question, you are asked to find the maximum torque that could be applied if someone continues to push with a force of 50 N. The force is given as 50 N, and again, the formula for torque is T = F*sin(angle).
To find the maximum torque, you need to maximize the value of sin(angle). The maximum value of sin(angle) is 1, which occurs when angle = 90 degrees or π/2 radians. Therefore, the maximum torque that could be applied with a force of 50 N would be T = (1.5 m)*(50 N)*(1) = 75 Nm or J.
So, to get the correct solutions:
2. At what angle would enough force be applied to achieve maximum torque?
The angle would be 90 degrees or π/2 radians.
3. If someone continues to push with a force of 50 N, what maximum torque could be applied?
The maximum torque that could be applied would be 75 Nm or J.