At body temperature (37C), K of an enzyme-catalyzed reaction is 2.3x10^14 times greater than k of the uncatalyzed reaction. Assuming that the frequency factor A is the same for both reaction, by how much does the enzyme the E^a?

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  2. šŸ‘Ž 0
  3. šŸ‘ 60
asked by Munavvar
  1. ln 2.3E14 = -Ea/RT
    Solve for Ea

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    2. šŸ‘Ž 0
    posted by DrBob222

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