To find the image length, of a 4-foot-tall object in a spherical mirror with a focal length of 2 feet, L=4(2/o-2)^2 can be used, where 2 is the distance, in feet, of the object from the mirror. What is the image length of the object when it is 1.5 feet away from the mirror?
To find the image length using the given formula, L=4(2/o-2)^2, where L is the image length and o is the distance of the object from the mirror, we can substitute the value o=1.5 feet into the equation.
Starting with the given formula: L=4(2/o-2)^2
Substitute the value o=1.5:
L=4(2/1.5-2)^2
Now, let's simplify the equation step by step:
L=4(2/(-0.5))^2
L=4(-4)^2
L=16(16)
L=256
Therefore, the image length of the object, when it is 1.5 feet away from the mirror, is 256 feet.
Repeated question with correct information in the question:
To find the image length, of a 4-foot-tall object in a spherical mirror with a focal length of 2 feet, L=4(2/o-2)^2 can be used, where o is the distance, in feet, of the object from the mirror. What is the image length of the object when it is 1.5 feet away from the mirror?
L = 4 (2/1.5 -2)^2
=4 (2/3 -2)^2
= 4 (-2/3)^2 = 4* 4/9 = 16/9