What is the center of a circle with endpoints (-4,3) and (6,-5)?
Is it (2,-2)?
(-4,3), (h,k), (6,-5).
The center = 1/2 of the total distance:
h - (-4) = (6 - (-4))/2
h + 4 = 10/2 = 5
h = 1
k-3 = (-5-3)/2
Solve for k.
Is it (2,-2)?
The center = 1/2 of the total distance:
h - (-4) = (6 - (-4))/2
h + 4 = 10/2 = 5
h = 1
k-3 = (-5-3)/2
Solve for k.