H2So4+NH4OH
Find the complete ionic equation
Find the spectator ions
Find the net ionic equation
I feel like my answer is wrong i tried
CIE: 2H+(aq)+So42-(aq)+2H4+(aq)---> 2NH4+(aq)+So42-(aq)+H2o (l)
See below
To find the complete ionic equation, you need to break down all the reactants and products into their ionic forms, showing the charges of the ions.
The given reaction is:
H2SO4 + NH4OH
To break down the reactants into ions:
H2SO4 → 2H+ + SO42-
NH4OH → NH4+ + OH-
Now let's write the complete ionic equation by combining the ions:
2H+ + SO42- + NH4+ + OH- → 2NH4+ + SO42- + H2O
Next, let's find the spectator ions. Spectator ions are the ions that appear on both sides of the equation and do not participate in the actual reaction. In this case, the spectator ions are SO42-. They appear on both sides of the equation, and therefore, they do not contribute to the net reaction.
Finally, to write the net ionic equation, you remove the spectator ions from the complete ionic equation:
2H+ + NH4+ + OH- → 2NH4+ + H2O
Thus, the net ionic equation for the given reaction is:
2H+ + NH4+ + OH- → 2NH4+ + H2O