The path that a football takes can be described by the euation h=25t-5t^2 where h is the height in meters, of the football, at t, in seconds. How high is the ball after 3 seconds?
h+25t-5^2
h= 25(3)-5(3)^2
h= 75- 45= 30 m
h = 25 t - 5 t ^ 2
Replace t with 3
h = 25 * 3 - 5 * 3 ^ 2
h = 75 - 5 * 9
h = 75 - 45 = 30 m
when will it hit the ground
Jjjj
To find the height of the ball after 3 seconds, we can substitute the value of t (3 seconds) into the equation h = 25t - 5t^2.
So, plugging in t = 3 into the equation, we get:
h = 25(3) - 5(3)^2
Next, we simplify the equation by calculating the values inside the parentheses and exponent:
h = 75 - 5(9)
Continuing, we multiply 5 by 9:
h = 75 - 45
Finally, we subtract 45 from 75 to get the final answer:
h = 30 meters
Therefore, the ball is at a height of 30 meters after 3 seconds.