Astronomy

The Hubble Space Telescope orbits at an altitude of 600 km above the Earth's surface. Assuming it is in a stable circular orbit, what is its velocity? For reference, the Earth's radius is 6400 km and Earth's mass is 6 x 10^24 kg.

The formula to solve for circular velocity is v(circ) = the square root of (GM/r)

The answer is 7500 m/s but I'm not sure how to get to this answer from this equation

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  1. r=6.4E6+.6E6 m

    Does that do it for you?

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    bobpursley

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