Physics

A projectile is launched with an initial speed V0. At its highest point, the projectile's speed is V0/2 . What was the launch angle above the horizontal?
(in deg)

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  1. horizontal velocity has to be vo/2, as that is the only component of velocity at the highest peak.

    V0^2=Vv^2 + (Vo/2)^2
    Vv^2=3Vo^2/4

    Vv= sqrt3/2 Vo

    launch angle=arctan Vv/Vh= (sqrt3/2 vo)/Vo/2= sqrt3

    angle= sixty degrees

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    bobpursley

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