How do I figure up how many days these hours equal up to?

Ytd=40.00. Used=8.00. Available 148.00
Ytd=80.00. Used=72.00. Available 8.00

1 day = 24 hours

How many 8hr days can I get out of 156 hours?

Is the answer 19.5

Yes.

To figure out how many days these hours equal up to, you need to know how many hours are in a day and then divide the total hours by that number.

First, let's start by looking at the Ytd (Year-to-date) values:
- Ytd = 40.00 hours for the first row
- Ytd = 80.00 hours for the second row

Next, let's focus on the Used values:
- Used = 8.00 hours for the first row
- Used = 72.00 hours for the second row

Now, let's calculate the remaining hours in the Available values:
- Available = 148.00 hours for the first row
- Available = 8.00 hours for the second row

To find out how many days these hours equal, we need to know the number of hours in a day. Typically, there are 24 hours in a day. Therefore, we can divide the total hours by 24 to find the number of days.

For the first row:
- Ytd = 40.00 hours
- Used = 8.00 hours
- Available = 148.00 hours

To calculate the number of days covered by Ytd, divide 40.00 hours by 24:
40.00 hours / 24 = 1.67 days (approximately)

To calculate the number of days used, divide 8.00 hours by 24:
8.00 hours / 24 = 0.33 days (approximately)

To calculate the number of days available, divide 148.00 hours by 24:
148.00 hours / 24 = 6.17 days (approximately)

For the second row:
- Ytd = 80.00 hours
- Used = 72.00 hours
- Available = 8.00 hours

To calculate the number of days covered by Ytd, divide 80.00 hours by 24:
80.00 hours / 24 = 3.33 days (approximately)

To calculate the number of days used, divide 72.00 hours by 24:
72.00 hours / 24 = 3.00 days

To calculate the number of days available, divide 8.00 hours by 24:
8.00 hours / 24 = 0.33 days (approximately)

So, the number of days for each row is:
- 1.67 days Ytd coverage, 0.33 days used, and 6.17 days available for the first row.
- 3.33 days Ytd coverage, 3.00 days used, and 0.33 days available for the second row.