a bathroom floor is covered by 15 tiles. each tile measures 18 in. by 18 in. how many floor tiles measuring 6 in. by 6 in. would be needed to cover the same area?
each large tile covers 3x3 = 9 small tiles.
So, what do you think?
How many 10 cm x10 cm tile you will need to cover a 10 m by 5 m floor.
To calculate the number of smaller tiles needed to cover the same area as the larger tiles, we need to compare their sizes.
First, let's calculate the area of the larger tiles:
Area of one larger tile = Length × Width = 18 in. × 18 in. = 324 in²
Since there are 15 larger tiles on the bathroom floor, we can find the total area covered by the larger tiles:
Total area covered by larger tiles = Area of one larger tile × Number of larger tiles = 324 in² × 15 = 4860 in²
Now, let's determine the area of the smaller tiles:
Area of one smaller tile = Length × Width = 6 in. × 6 in. = 36 in²
To find out how many smaller tiles are needed to cover the same area, divide the total area covered by larger tiles by the area of one smaller tile:
Number of smaller tiles needed = Total area covered by larger tiles ÷ Area of one smaller tile = 4860 in² ÷ 36 in² = 135
Therefore, you would need 135 tiles measuring 6 in. by 6 in. to cover the same area as 15 tiles measuring 18 in. by 18 in.