Together Marc and Paul have $32 Marc has $4 less than twice the amount Paul has. How much does each man have?

How do I set this up -4+2x=32 ??

M = 2 P- 4

so
P + 2P-4 = 32
3 P = 36
P = 12

then Marc has 24 - 4 = 20

Thank you!!

You are welcome.

How much does Polioa have?

To set up this problem, let's define variables for the amounts that Marc and Paul have. Let's say Marc has M dollars and Paul has P dollars.

According to the problem, Marc has $4 less than twice the amount Paul has. This can be written as:
M = 2P - 4

We also know that together, Marc and Paul have $32. This can be written as:
M + P = 32

Now we have a system of two equations:
M = 2P - 4
M + P = 32

To solve this system of equations, we can use substitution or elimination. Let's use the substitution method.

First, we can substitute the expression for M from the first equation into the second equation:
(2P - 4) + P = 32

Simplifying the equation, we get:
3P - 4 = 32

Next, we can add 4 to both sides of the equation:
3P = 36

Finally, we divide both sides of the equation by 3 to solve for P:
P = 12

Now that we have the value of P, we can substitute it back into one of the original equations to find M. Let's use the first equation:
M = 2P - 4 = 2(12) - 4 = 24 - 4 = 20

Therefore, Marc has $20 and Paul has $12.